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Copy pathbinary_tree.py
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93 lines (82 loc) · 2.86 KB
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class BinaryNode:
def __init__(self, data):
self.left = None
self.right = None
self.data = data
# https://stackoverflow.com/questions/2598437/how-to-implement-a-binary-tree
class BinarySearchTree:
def __init__(self):
self.root = None
self.size = 0
def add(self, val):
if self.root is None:
self.root = BinaryNode(val)
else:
self._add(val, self.root)
def _add(self, val, node):
if val < node.data:
if node.left is not None:
self._add(val, node.left)
else:
node.left = BinaryNode(val)
else:
if node.right is not None:
self._add(val, node.right)
else:
node.right = BinaryNode(val)
self.size += 1
def find(self, val, node):
if self.root is None:
return None
elif val == node.data:
return node
elif val < node.data and node.left is not None:
self.find(val, node.left)
elif val > node.data and node.right is not None:
self.find(val, node.right)
# returns array of nodes by inorder traversal
def inorder(self, node):
if node is None:
return []
left = self.inorder(node.left)
right = self.inorder(node.right)
return left + [node.data] + right
# get height of the bst
def get_height(self):
return self._get_height(self.root)
def _get_height(self, node):
if node is None: return 0
return max(1 + self._get_height(node.left), 1 + self._get_height(node.right))
# Prints kth maximum value in a binary search tree
# reverse inorder traversal will return nodes sorted in desc order
def kth_maximum(self, node, k):
if k <= 0 or node is None:
return k
k = self.kth_maximum(node.right, k)
k -= 1
if k == 0:
print node.data
return self.kth_maximum(node.left, k)
# Find nodes at "k" distance from the root
def kth_level(self, node, k, nodes=[]):
if node is not None:
if k == 0:
nodes += [node]
else:
self.kth_level(node.left, k - 1, nodes=nodes)
self.kth_level(node.right, k - 1, nodes=nodes)
return nodes
# Fills ancestors of a given target node into the result array
# returns true if node is found in the tree
def fill_ancestors(self, node, target, result):
if node is None:
return False
if node.data == target:
return True
in_left = self.fill_ancestors(node.left, target, result)
in_right = False
if not in_left:
in_right = self.fill_ancestors(node.right, target, result)
if in_left or in_right:
result += [node]
return in_left or in_right